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Find the length of the major axis of the equation x^2 + 4y^2 = 4
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@dusty
divide by 4 ... what do you get?
my answer is 2 but idk if its right or wrong
reduce it to the form of \[x ^{2}/a ^{2} + y ^{2}/b ^{2}= 1\]
you should get \[x ^{2}/4 + y ^{2}/1 = 1 \]
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length of the major axis is ' 2a ' if a>b and is ' 2b ' if b>a
so for b i have to put 1
yes . a^2 = 4 so a=2 and b^2=1 so b=1 .. as a>b , length is 2a
ohh.. thank you :)
can you guys help me with another one ?
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