Factor by grouping
32x^2-8x-4

Question

Factor by grouping
32x^2-8x-4

andriod09 · Answer

$$32x^2-8x-4$$ right?

anonymous · Answer

yep @andriod09

andriod09 · Answer

okay, lets see. do you know how to factor in the first place?

anonymous · Answer

Yes, I have the answer,im just stuck as to how to get it. the asnwer is 4(4x+1)(2x-1)

andriod09 · Answer

so then lets work from there. 
$$4(4x+1)(2x-1)$$ what would you do first?

anonymous · Answer

FOIL

andriod09 · Answer

do FOIL for me then, step by step, like do F, then do O, then I, then L in different posts, or use it slowly in the same posts. use line breaks, is what i mean.

anonymous · Answer

4x*2x=8x^2

anonymous · Answer

4x*1=4x

anonymous · Answer

1*2x=2x

anonymous · Answer

1*-1=-1
--------
O= should have been a -4 not 4.

anonymous · Answer

8x^2-4x+2x-1
--------------
8x^2-2x-1

andriod09 · Answer

you're missing something, redo your steps 1-3

anonymous · Answer

i thought you distribute the 4 at the end so then it would be 4(8x^2-2x-1)

andriod09 · Answer

this is how i would do it, tell me if you see any mistakes.
$$4(4x+1)(2x-1)$$ $$(16x+4)(8x-4)$$ then you would double it, as far as i know. i'm sorry if i didn't help. relized i haven't done this in nearly 3 years. xD

anonymous · Answer

Thaat sokay i figured out my missing step thanlks :D

andriod09 · Answer

NP. thanks! and your welcome!