Question

(5x-8) (2x-5)

Answer 1

5x(2x-5)-8(2x-5) <-- try to solve this

Answer 2

um

Answer 3

use multiplication

Answer 4

okay i got 10x-25 -16x+40

Answer 5

10x^2-25x-16x+25
which would be
10x^2-41x+25

Answer 6

great now solve further..

Answer 7

Correct but remember 10x is 10 x ²

Answer 8

um

Answer 9

idk what to do now

Answer 10

yea when u multiply x's it becomes square

Answer 11

x.x=x^2

Answer 12

When you multiply 2 numbers with x's the x's multiply too...which becomes x times x which is x squared...or x²

Answer 13

10x2

Answer 14

and then what

Answer 15

what about the 16x

Answer 16

-4x2

Answer 17

now u hv 10x^2-41x+25.. after adding x's

Answer 18

i mean -6x2

Answer 19

16x stays the same...do you have any other x's? ***you cannot combine x² and x.

Answer 20

oh

Answer 21

wait perhaps I've looked wrong let me do this out

Answer 22

so its
10x2 -41x+25

Answer 23

(5x-8) (2x-5)

10x² - 25x - 16x + 40

so yes 10x² -41x + 40

Answer 24

i have like 13 problems like these

Answer 25

did u get some idea how to do it?

Answer 26

so thats your final answer

Answer 27

Use the FOIL method i used above for this e.g

Answer 28

(7w+5)(11w-3)

Answer 29

let me do it over:
5x(2x-5)-8(2x-5)
10x^2-25x-16x+40
10x^2-41x+40

Answer 30

so 77w2+55w-33w-15

Answer 31

yea use the same trick with this:
7w(11w-3)+5(11w-3) <- they just replaced x with w's

Answer 32

is that right

Answer 33

u got first one right 7w x 3 = 21w

Answer 34

so it will be 77w^2-21w+55w-15
77w^2+34w-15

Answer 35

yup
the next one is *b-2)(b2-b+1)

Answer 36

try it..

Answer 37

b(b^2-b-1)-2(b^2-b+1)

Answer 38

um

Answer 39

its not tht hard, give it a try

Answer 40

i got 2b2-2b-1b-2b2-2b+2

Answer 41

ur second part is right..

Answer 42

my first part is wrong

Answer 43

when u multiply bxb^2 it will be b^3

Answer 44

so its b3

Answer 45

right!

Answer 46

same goes with the next one.. u just add power to the variable when u multiply

Answer 47

so what will it look i like

Answer 48

b(b^2-b-1)-2(b^2-b+1)
\[b ^{3}-b ^{2}-b-2b ^{2}+2b-2\]

Answer 49

can you solve that