Question

What is the 35th term of the arithmetic sequence where a1 = 13 and a17 = -83?

-200
-197
-194
-191

Answer 1

@ghazi @ghazi @ghazi

Answer 2

ust tn = a+(n-1)d

Answer 3

*use

Answer 4

an=a1+(n-1)d
since a17 is given
it is given that
-83=13+16d
-96=16d

d=-6
a35=a1+34d
put value of d

Answer 5

how would you put the a into the calculator so it goes lower like a reverse to the power of

Answer 6

i know its like some form of the parenthesis

Answer 7

Let a1 and a17 and a35 represent terms a sub 1, a sub 17, and a sub 35, respectively.

Answer 8

The nth term of an arithmetic sequence is the first term + (n-1)*d where d is the common difference of the sequence.

Answer 9

Terms a1 and a17 are 16 places apart.

So, a17 = a1 + 16 d

-83 = 13 + 16d

-96 = 16d

-6 = d

Please check this.

Answer 10

I get that I believe

Answer 11

an = a1 + (n-1)*d

a35 = 13 + (35-1)*(-6)

Answer 12

a35 = 13 + (35 - 1) *(-6)

a35 = 13 + 34 * (-6) = ? --->@tinaballerina

Answer 13

so -191 , right?

Answer 14

I got -203. Let me check my sign-us-ses

Answer 15

13 + 34*(-6) = 13 - 204 = -191

Answer 16

I multiplied (-6) by 36 for some reason and messed up.

Answer 17

Ah I see. Glad to see someone takes time to help! Thank you I very much appreciate it, would you mind checking over my few problems? I answered them.

Answer 18

Are these other problems in separate threads or ones you have not yet posted or what?

Answer 19

I have not posted them. I have the whole problems I can post them in the comment

Answer 20

One question per thread works better for me because I have to scroll up and down to get the details of a problem. Then, if several problems and the details thereof intermingle, it makes for a mess.

Answer 21

Okay Ill link you per problem?

Answer 22

This @ping system is not working. The send a message via the envelope is working. You can send a message, or I can find you.

Answer 23

Okay theres not many questions being asked so ill ask in the math lol