P is any point on the median AD of ΔABC. Show
that ar(APB) = ar(ACP)

Question

P is any point on the median AD of ΔABC. Show
that ar(APB) = ar(ACP)

mathslover · Answer

@ParthKohli

parthkohli · Answer

ar?

mathslover · Answer

area

amistre64 · Answer

congruent triangle thrms?

mathslover · Answer

yes sir

parthkohli · Answer

APB and ACP are not necessarily congruent. :-\

mathslover · Answer

Well the chapter name was " Area of parallelograms and triangles " but I am sure that it will use congruent angle theorems or "mid-pt. theorem"

amistre64 · Answer

|dw:1362761588096:dw|

mathslover · Answer

We know that : the median of a triangle divides a triangle into two congruent triangles ( equal areas )  ..

parthkohli · Answer

A triangle $b = 2 $ and $h = 2$ has the same area of one with $b = 4$ and $h = 1$. So I can pretty much assure that they  are not necessarily congruent

amistre64 · Answer

the area of a triangle is height times base divided by 2

area of the left is hx/2, area of the right is hx/2

parthkohli · Answer

LOL, nice! Didn't think of that one