Question

*********FAN AND MEDAL*******
2x + 3y = 30... Find 3 diffrent combinations of x and y's solution (I already have one which is x = 6, and y = 6. PLEASE HELP ME!!!

Answer 1

@Mertsj

Answer 2

@quarkine come on can you help me out Sasuke?

Answer 3

@dusty any ideas on this?

Answer 4

@amistre64 @ash2326 @johnweldon1993 @mathstudent55

Answer 5

You want me to help you?

Answer 6

yes, if you can

Answer 7

Pick a number.

Answer 8

3

Answer 9

Multiply that number by 2

Answer 10

6

Answer 11

Subtract that answer from 30

Answer 12

24

Answer 13

Divide that answer by 3

Answer 14

8

Answer 15

There you go. If x = 3, y = 8

Answer 16

Pick another number

Answer 17

5

Answer 18

Multiply that number by 2

Answer 19

10

Answer 20

Subtract that answer from 30

Answer 21

20

Answer 22

Divide that answer y 3

Answer 23

6.66666

Answer 24

20/3 will do just as well. There you go. If x = 5, y = 20/3

Answer 25

How many more answers do you need?

Answer 26

It is for a realy long word problem in math, and I need whole numbers. I just simplified it for the question on here

Answer 27

and just 1

Answer 28

2x + 3y = 30

3 = 2(1)+1 ; gcd(3,2) = 1
2 = 1(2)+0

0
0 1
0-1(1) = -1 ; x' = -1

1
1 0
1-0(1) = 1 ; y' = 1

1 = 2x' + 3y'

30 = 2(30x') + 3(30y')

X = 30x' + 3n
Y = 30y' - 2n

should solve for all the integer solutions

Answer 29

http://www.wolframalpha.com/input/?i=2%28-30%2B3n%29%2B3%2830-2n%29

just to be sure ;)

Answer 30

thank you

Answer 31

2x + 3y = 30 represent a line in the x-y plane.so any point on the line will satisfy this condition.So find the solution graphically .Or solve as y=(30-2x)/3 .Put any value in x and you will get a y. hence you can get as many pair as you like..