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Divide: (3x-15)/(14y) ÷ (x^2-15x+50)/7
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\[((3x-15)\div14y)(7/((x-10)(x-5)))\]
extract the 3 from the 3x-15 which gives u 3(x-5)
\[\frac{ 3x-15 }{ 14y }\div \frac{ x^2-15x+50 }{ 7 }\]
now u can simplify more
\[\frac{ 3(x-5) }{ 14y }\times \frac{ 7 }{ x^2-15x+50 }\] I also went ahead and did the recipricle... which I chould've done to begin with
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yup then factorize the x^2-15x+50
to (x-5)(x-10)
\[\frac{ 3(x-5) }{ 14y }\times \frac{ 7 }{ (x-5)(x-10) }\]
yup now cancel the x-5 and 7/14 is 1/2
so in the end you should get 3/(2y(x-10))
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yea, that's what I got. Thank you!
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