Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Vertical Motion Model,can someone help?h=-16t^2+30t+6.How logn will it take the ball to reach the maximum height?What is teh balls maximum height?Whats the range?I dont understand how to solve this?

OpenStudy (abb0t):

You could take the derivative of the function, set it equal to zero and solve for "t".

OpenStudy (abb0t):

Plug in that value into ur initial function to find the max height.

OpenStudy (johnweldon1993):

correct...the derivative of -16t² + 30t + 6 is?

OpenStudy (anonymous):

|dw:1362788795875:dw|

OpenStudy (johnweldon1993):

or like that...yes that is your t...now plug that into your original equation..this will solve for height

OpenStudy (anonymous):

|dw:1362788999296:dw|

OpenStudy (johnweldon1993):

that would be correct :)

OpenStudy (anonymous):

So the ball would take 0.9375 seconds to reach its maximum height.And the maximum height would be is 20.0625.The range would be 6 is less then or equal to h is less than or equal to 20.0625.Correct?

OpenStudy (johnweldon1993):

That would be correct...sorry for the delay :)

OpenStudy (anonymous):

Thanks :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!