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The power generated by a hydroelectric plant is directly proportional to the flow rate through the turbines, and a flow rate of 5570 imperial gallons of water per minute produces 43.3 MW. How much power would you expect when a drought reduces the flow to 5000 gal/min?
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Ok we are working with ratios and fractions here. 5570/ 43.3 and we have to fine this 5000/? We can just divide the first equation like this: 43.3 by 5770 and find how much MPH each gallon produces and multiply that by 5000. So we have 1/ about 0.008 and we multiply this by 5000 and we have 40. So we get 40 MPH
unfortunately it isn't right, but thanks for the help :)
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