Question

3x^2-2x+7=0, then (x-1/3)^2

Answer 1

For x²-2x+7=0, use quadratic formula.

For (x-1/3)², it equals (x-1/3)(x-1/3) then expand it using FOIL or box method.

Answer 2

those r not two seperate questions those r 1

Answer 3

\[3x^2-2x+7=0\] then \[{ (\frac{ x-1 }{ 3 })}^2\]

Answer 4

You mean, find the value of \(\left(\dfrac{x-1}{3}\right)^2\)?

Answer 5

yes

Answer 6

Well, first, find value of x from x²-2x+7=0. Use quadratic formula.

Then plug in value of x into \(\left(\dfrac{x-1}{3}\right)^2\).

Answer 7

non calculator i did that it takes time

Answer 8

Well, it does. Be patience!

Answer 9

I'm surprised you know calculus but not this.

Answer 10

hmm xD i did this figuring out any new methods

Answer 11

as simply as possible