Choose the slope-intercept equation of the line that passes through the point (-5, -1) and is perpendicular to y = five halvesx + 2.

y = two fifthsx + 1

y = -five halvesx - 27 halves

y = -two fifthsx - 3

y = five halvesx + 23 halves

Question

Choose the slope-intercept equation of the line that passes through the point (-5, -1) and is perpendicular to y = five halvesx + 2. 

 y = two fifthsx + 1 

 y = -five halvesx - 27 halves 

 y = -two fifthsx - 3 

 y = five halvesx + 23 halves

anonymous · Answer

for a line1 to be perpendicular to a line2 the slope of line1 must be the inverse negative of line2 knowing$$y=mx+b$$ we can see the slope of the given line is $$5/2$$flip the fraction and put a negative infront of it to get the slope of the perpendicular line which is$$-\frac{ 2 }{ 5 }$$since only one option has that slope the answer is the third one (im assuming its multiple choice)

anonymous · Answer

m= slope, b=y-intercept