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1st 2nd and 3rd derivative of 2x/ 3x-2?? helpp
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remember the quotient rule here ...let 2x = f and 3x - 2 = g
f'=(3x-2)(2)-(2x)(3) / (3x-2)^2?
correct....so that would equal the first derivative
well simplified I believe it's -4 / (3x-2)^2 but how would I go about the second derivative?
you are correct for the first derivative....also expand the denominator though so -4/9x² - 12x + 4 right?
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for the second derivative...do the SAME thing.... let -4 be f and 9x² - 12x + 4 be g so g * derivative of f - f * derivative of g all over g squared
ok, thank you
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