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Mathematics 13 Online
OpenStudy (anonymous):

how do i find the zeros of y=xcos2x?

OpenStudy (anonymous):

is it xcos2x or xcos^2x

OpenStudy (anonymous):

xcos2x

OpenStudy (anonymous):

here is easy method, graph it then check all the values which equals 0 here they r 0, -pi/4 and pi/4

OpenStudy (anonymous):

but how do i do it algebraically

OpenStudy (anonymous):

\[x \cos(2x) = 0\] we know if we use x = 0 everything is gonna be 0...so our first answer is 0 next|dw:1362960698108:dw||dw:1362960839281:dw||dw:1362960941000:dw|

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