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Algebra 2. Multiple choice? Please help :/
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With the restriction of \[x \neq0\] which of the following is the simplified form of \[\frac{ 6x^4 }{ 4x^9 }\times \frac{ 12x^2 }{ 3x^5 }\]
\[A. \frac{ 6 }{ x^2 }\]
\[B. 6x^8\]
\[C. \frac{ 6 }{ x^8 }\]
\[D. 6x^2\]
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\[\frac{6x^4*12x^2}{4x^9*3x^5}\]
\[\frac{6*12*x^2*x^4}{3*4*x^5*x^9}\]
additional help - http://tutorial.math.lamar.edu/Classes/Alg/IntegerExponents.aspx
Thanks! I think I got it from here :D
\[\frac{2*3}{x^3*x^5}\]
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That should be enough help
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