Is r√r - 3r√r + 4r√r equal to 2r or 2√r?
I know it has to be one of the two because 1 - 3 + 4 = 2, but I'm not sure if you are supposed to keep the radial sign or not.

Question

Is r√r - 3r√r + 4r√r equal to 2r or 2√r?
I know it has to be one of the two because 1 - 3 + 4 = 2, but I'm not sure if you are supposed to keep the radial sign or not.

hartnn · Answer

factor out r√r,
so, r√r(1-3+4) = ... ?

anonymous · Answer

it's just r once you've done that, right?

anonymous · Answer

well, 2r I mean

hartnn · Answer

whats 1-3+4=...?
then multiply that with r√r
and its none of these : 2r or 2√r

anonymous · Answer

Then wouldn't that be 4r? And then the square of 4 is 2. The only other thing I can think of is that it could be 2r√r once it's been multiplied.

hartnn · Answer

' it could be 2r√r once it's been multiplied. ' <----it is.
r√r(1-3+4) = r√r(2) = 2r√r.

anonymous · Answer

Ahh, sorry. That's right! I'm not sure what I was thinking. Thank you.

hartnn · Answer

welcome ^_^