Question

hep with this function, trying to find b

f(x)=(1/3) b^x;f(1/2)=20

Answer 1

ok... so you know that

\[20 = \frac{1}{3} \times b^{\frac{1}{2}}\]

multiply both sides by 3

then square both sides to find the value of b

Answer 2

I noticed this question was posted by two different people. Were you both able to figure this one out?

Answer 3

whaaa? fo reals? who else posted it?

Answer 4

I think you found it lol

but were you able to figure it out?

Answer 5

first tell me if it was a proper technique?

Answer 6

yes it's the way to do it

Answer 7

campbell_st is on the right track

Answer 8

i got 3600

Answer 9

would you say that is correct?

Answer 10

f(x)=(1/3) b^x

20=(1/3) b^(1/2)

20*3 = b^(1/2)

60 = b^(1/2)

sqrt(b) = 60

b = 60^2

b = 3600

so you got it

Answer 11

thanks guys, i love it here. ya'll make learning fun!