hep with this function, trying to find b

f(x)=(1/3) b^x;f(1/2)=20

Question

hep with this function, trying to find b

f(x)=(1/3) b^x;f(1/2)=20

campbell_st · Answer

ok... so you know that

$$20 = \frac{1}{3} \times b^{\frac{1}{2}}$$

multiply both sides by 3

then square both sides to find the value of b

jim_thompson5910 · Answer

I noticed this question was posted by two different people. Were you both able to figure this one out?

anonymous · Answer

whaaa? fo reals? who else posted it?

jim_thompson5910 · Answer

I think you found it lol

but were you able to figure it out?

anonymous · Answer

first tell me if it was a proper technique?

jim_thompson5910 · Answer

yes it's the way to do it

jim_thompson5910 · Answer

campbell_st is on the right track

anonymous · Answer

i got 3600

anonymous · Answer

would you say that is correct?

jim_thompson5910 · Answer

f(x)=(1/3) b^x

20=(1/3) b^(1/2)

20*3 = b^(1/2)

60 = b^(1/2)

sqrt(b) = 60

b = 60^2

b = 3600

so you got it

anonymous · Answer

thanks guys, i love it here. ya'll make learning fun!