Please Help!!

Find the equation of the tangent line to the following curve at the point (0, pi)

sin(x+y)=2x

Question

Please Help!!

Find the equation of the tangent line to the following curve at the point (0, pi)          

sin(x+y)=2x

anonymous · Answer

do you know about inverse trig functions?

anonymous · Answer

no

anonymous · Answer

i've tried everything can you please get me the answer?

anonymous · Answer

@RadEn just helped me hopefully he can help you . . .otherwise I'll let you know if I have an idea

anonymous · Answer

ok

raden · Answer

we have to derive implicitly !

anonymous · Answer

how do i do that?

raden · Answer

sin(x+y)=2x
cos(x+y) + cos(x+y) y' = 2
cos(x+y) (1 + y') = 2
1 + y ' = 2/ cos(x+y)
y ' =   [2/cos(x+y)]   -  1

raden · Answer

now, subtitute x=0 and y=pi to equation above to get the slope (m)

anonymous · Answer

y-y1=m(x-x1)?

raden · Answer

m = y '(0,pi) =  [2/cos(0+pi)] - 1 = 2/cospi  - 1 = 2/(-1) - 1 = -2-1=-3

anonymous · Answer

got it!!!!!!

anonymous · Answer

thank you!!

anonymous · Answer

y=-3x+pi

raden · Answer

it just a slope 
to get the slope equation use the formula like u said :
y-y1=m(x-x1)

EXACTLY, U ARE RIGHT :)

anonymous · Answer

can i ask you one more question?

anonymous · Answer

yea sorry about that I knew it was either inverse trig functions or implicit differentiation but I could not remember how to do implicit at the moment

raden · Answer

sure, but close this, and posting in the new question :)

anonymous · Answer

ok

anonymous · Answer

I would have given that medal to @RAdEn he is the one who helped you

anonymous · Answer

thank you !!