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Set up the definite integral that represents the area of the region, inside r = 1 + cosθ but outside r= - cosθ
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you know how the graph of each equation looks like?
http://www.wolframalpha.com/input/?i=r%3D1%2Bcos%5Ctheta http://www.wolframalpha.com/input/?i=r%3D-cos%5Ctheta
first find theta where they cross: -cosθ = 1 + cosθ 2cosθ=-1 cosθ=-1/2 θ=2Pi/3 and θ=4Pi/3
Now notice that the graph is siymetrical to x axis, so you only will need to take care of the upper part. Split the integral in parts 1 and 2: |dw:1363004262984:dw| 1º part is for 0<θ<Pi/2 2º part for Pi/2< θ <2Pi/3
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