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Solve the following system of equations. 2x + y = 3 x = 2y - 1
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plug in x=2y-1 in the first equation, 2x +y=3 you get 2 (2y-1)+y=3 can you solve this equation which is only in 'y' and find y ?
y+5/6
how ? 4y-2+y=3 5y=3+2 5y=5 y=1 got this ?
i didnt distribute first i did something different ; how would i do this one Solve the following system of equations. 3x + 2y - 5 = 0 x = y + 10
put x=y+10 in 3x+2y-5=0 so, 3(y+10) +y -5=0 distribute first.
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y=8.75
3y+30+y-5=0 4y+25=0 y = -25/4 = - 6.25 how u got 8.75 ?
i add 30+5 instead of subtracting
k, now clear ?
Solve the following system of equations by the substitution method. 10x + 10y = 1 x = y - 3
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new question , new post plese ?
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