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Mathematics 21 Online
OpenStudy (anonymous):

Please Help: Factoring Trinomials Word Problem!

OpenStudy (anonymous):

I have to create two questions and their answers for a (math) gameshow.

OpenStudy (anonymous):

For example: Question for Host: x2 + 6x + 5 is the product of these two binomials Expected Question from Contestant: What is (x + 5)(x + 1)?

OpenStudy (anonymous):

The 1st problem I came up with was as follows: Question for Host: y6 + y9 + 5 is the product of these two binomials? Expected Question from Contestant: What is (y + 3)(y + 3)? Would that be correct?

hartnn (hartnn):

what are y6 and y9 ?

hartnn (hartnn):

and no...

OpenStudy (anonymous):

Ohhh it would be: y2 + y9 + 6?

hartnn (hartnn):

you should use, y^2 -sum y +product =0

hartnn (hartnn):

what you have used is y^2+product y +sum =0 which is incorrect.

OpenStudy (anonymous):

Ok thanks . . . again x's 4(?) :D

hartnn (hartnn):

thank me after you get your question fully done... so, what you get now ?

OpenStudy (anonymous):

Well I just wanted to know if I was right or wrong, but now I guess I would get y^2 - 6y +9

hartnn (hartnn):

why -6 ,it'll be +6 ,right ? (y+3)(y+3)=y^2+6x+9

OpenStudy (anonymous):

Umm yes I guess :) And that would be because 3*3=9 & 3 + 3 = 6

hartnn (hartnn):

oh...that sum was for sum of roots, for (x+3)(x+3), roots are -3,-3 sum = -3+(-3) = -6 and product = -3*-3 = 9

OpenStudy (anonymous):

So in the end I would get: Question for Host: y^2 + 6x + 9 is the product of these two binomials? Expected Question from Contestant: What is (y + 3)(y + 3)?

hartnn (hartnn):

yes, thats correct.

hartnn (hartnn):

just a typo, y^2+6y+9

OpenStudy (anonymous):

Now can I thank you?

hartnn (hartnn):

lol :P ok...as you wish,,,

OpenStudy (anonymous):

Ok thanks . . . again x's 5(?) :D

hartnn (hartnn):

welcome ^_^

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