two dice are thrown prob(atleast 5 comes)=? and Prob(atmost 5 comes)=?
2 out 12 or 1 out 6
idk about the second one the way you are asking these are confusing
@mvrc1996 how comes 2/12=1/6
cause you reduce the fraction
u didn't get my point how 2/12 comes
total no of outcomes are 36
i seeee hol don
4/36 =1/9
idk about the second one though
okay, no pblm @mvrc1996
but can u mention that 4 favourable outcomes
2+3=5 4+1=5 3+2=5 1+4=5
k
This is the set of possible outcomes: 1 2 3 4 5 6 1 2 3 4 5 6 7 2 3 4 5 6 7 8 3 4 5 6 7 8 9 4 5 6 7 8 9 10 5 6 7 8 9 10 11 6 7 8 9 10 11 12 Each has probability (1/6)²=1/36. At most 5: there are 10 possibilities, so 10/36 = 5/18
plse mention which are 10 favourable outcomes
(1,0), (1,1), (1,2), (1,3), (1,4), (1,5), (1,6) (2,0), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6) (3,0), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6) (4,0), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6) (5,0), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6) (6,0), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,0), (1,1), (1,2), (1,3) (2,0), (2,1), (2,2) (3,0), (3,1) (4,0)
what about aleast 5 comes situation
@ZeHanz i think u ahve given me the answer for the aleast situation
Oops, I misread it. At least 5, so 5 or more. A lot of counting! Unless...we count the complement: max. 4. (counting) I counted 6 possibilities for max. 4 (look it up in my table) This means 5 or more will be 36-6=30 possibilities, so p=30/36=5/6
prob(atmost ) = 30/36 and prob(atleast) =10/36
But atmost ki liye to 15 favourable outcomes are cmg
No, I think you made a mistake: p(sum <=5)=10/36 (10 possibilities). p(sum >=5)=30/36 (30 possibilities).
what <= stands for
<= smaller than or equal, so: at most >= greater than or equal, so: at least.
but atmost condition ki liye , there 15 favourable outcomes (1,0), (1,1), (1,2), (1,3), (1,4),(2,0), (2,1), (2,2), (2,3),(3,0), (3,1), (3,2)(4,0), (4,1) and (5,0)
0 is not on a die
BTW, what is "ki liye"?
it's hindi word
Now I begrijp
It is a dutch word :D
i know , its meaning "understand"
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