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Help with the following integral: ∫(from 0 to pi/2) sin^2(x) cos^2(x) sorry I don't really know how to write integrals down on the computer :/
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I got to this point : sin^2(x) (1+cos^(x) /2 )
change that into sin2x
Well I can get 1/2 sin2x with (sinxcosx)^2 would that work?
no ... there is square again.
but (sinxcosx)^2 = (1/2sin2x)^2 = 1/4(sin^2(2x))?
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yes ... but still that will not work. there is square ... but we can change it into cos4x
Yeah I see it.. using basic trig! thanks :)
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