Question

the area of a triangle is 64square meters and the base is one-half times the height. find the triangles height

Answer 1

First try writing out two equations, one that describes the area of a triangle, and then one that describes the relation between this triangle's base and height, as given.

Answer 2

kk so area is base* height *.5= area

Answer 3

Good, b*h*1/2 = a. How about another for the relation between the base and height of this triangle?

Answer 4

Let h = height, then
b = (1/2)h
A = (1/2)bh
64 = (1/2)(1/2)h*h
64*4 = h^2
256 = h^2
h = 16

Answer 5

wait so its 16?

Answer 6

here you know the formula for area correct.
well plug in what you know.\[64=\frac{ 1 }{ 2 }(\frac{ x }{ 2 })x\]

Answer 7

but then wht?

Answer 8

then solve, \[64(\frac{ 2 }{ 1 })=(\frac{ x }{ 2 })(\frac{ x }{ 1 })\]

Answer 9

i got 128 but idk

Answer 10

\[128=\frac{ x ^{2} }{ 2 }\] you combine the right side

Answer 11

so multiply 128 but 2 and then find the square root?

Answer 12

yep you got it.