Okay so I have a couple more questions about logarithms.
"Which shows 3^-4 = 1/18 in logarithmic form?" A.\[\log _{-4}3 = \frac{ 1 }{ 81 }\]B.\[\log _{3}(-4) = \frac{ 1 }{ 81 }\]C.\[\log _{3}(\frac{ 1 }{ 81 }) = -4\]D. \[\log _{-4}(\frac{ 1 }{ 81 }) = 3\]
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U know how to did i change it ?
1/18 or 1/81
She meant 81
I meant 1/81, sorry
I don't quite understand how you got the answer, please feel free to explain!
Eyad explain her,please
Here is the law of changing : \[\Large Log_{a}b=c \] TO change that in to exponential : \[\Large a^{c}=b\]
Oh okay! I understand now, thanks!
I have just one more question, if that's okay?
Sure ,Feel free to ask anything :P
Step 1:\[4^{x-1}=64^{x+3}\]Step 2:\[4^{x-1}=(4^{3})^{x+3}\]Step 3:\[4^{x-1}=4^{3x+9}\] What would be the next step? A. 4 = 3x + 9 B. x - 1 = -(3x + 9) C. x - 1 = x + 3 D. x - 1 = 3x + 9
Since Base (4) = Base (4) therefore power =power which mean X-1=3x+9
Okay! Thank you, again!
:)
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