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|(2x)/(7)-5|≥7 absolute value
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\[\frac{ 2x-35 }{ 7 }\ge7\]\[2x-35\ge49=2x \ge84=x \ge42\]
deena its 2 root,x≥42 or x?
-7 ≥ (2x/7)-5 ≥ 7 -7+5 ≥ 2x/7 ≥7+5 (-2)(7) ≥ 2x ≥ (12)(7) -14 ≥ 2x ≥ 84 -14/2 ≥ x ≥ 84/2 =-7 ≥ x ≥ 42
chooper,the 1st step what did you do?
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that is how you should solve absolute values. put the 7 side by side. -7 ≥ (2x/7)-5 ≥ 7 one the left side, 7 will become negative because it was transposed. and then, at the right side, it will be the same as the given equation.
then transpose -5 to the two sides of the equation. then solve. it's just like solving a simple equation. You can also solve it separately.
good,tnx
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