Question

Part 1: Explain, in complete sentences, whether or not the expression x2 – 121 fits one of the special patterns. If so, which one? (2 points)

Part 2: Explain how the polynomial is factored. (2 points)

Part 3: Provide the factors. (2 points)

Answer 1

it fits that is (a+b)(a-b)

Answer 2

\[x^2-121=(x+11)(x-11)\]

Answer 3

got it @raebaby420 ?

Answer 4

No

Answer 5

part 1---> it fits in the special series that if 2 numbers like a and b are there so \[a^2-b^2=(a+b)(a-b)\]

Answer 6

well first of all it is of the form \(a^2-b^2\)

so you can immediately split it as \[(a^2-b^2)=(a+b)(a-b)\]

this how we factor the polynomial ..with that said can you tell which will be the factors ?