Solve for n:

(4n)^3 (2^n + 2) = (4^2)^n – 1

Question

Solve for n: 

(4n)^3 (2^n + 2) = (4^2)^n – 1

anonymous · Answer

ok first what can you do to the first term
 sorry if it looks like i'm stalking you, these are the kinds of problems I love, kind of a nerd

anonymous · Answer

No problem, hahah I really appreciate when someone helps me.

4^3n

anonymous · Answer

is this correct?

anonymous · Answer

it would be correct if the equation war (4^n)^3
well lets look at it
(4xn)^3 when you have an exponent touching parenthesis with no adding of subtracting in them then you use the exponent on everything, does that make sense?

anonymous · Answer

no, it does not

anonymous · Answer

make sense..

anonymous · Answer

ok well if you have something like$$(x+y)^2$$then tou have to put it out like this$$(x+y)(x+y)$$but if you have multiplication or division instead of addition or subtraction like$$(xy)^2$$then it simplifies to this$$x^2y^2$$

anonymous · Answer

ok so then it is 4^3n^3

anonymous · Answer

I'm getting confused now. OK this is a problem that we're probably over thinking. what I would suggest stepping away from this problem for a little while, do another one and then come back.

anonymous · Answer

Ok. I am sorry for confusing and causing a problem for you. Thank you very very much for everything

anonymous · Answer

oh no problem, I'm sorry I couldn't figure this one out.

anonymous · Answer

No worries. Thank you for trying :)