Ask
your own question, for FREE!
Mathematics
9 Online
My answer is A Which of the following is the solution to the equation 25(z + 4) = 125 ? (3 points) Answer z = 5.5 z = 3.5 z = -2.5 z = -0.5
Still Need Help?
Join the QuestionCove community and study together with friends!
Are you sure you have the correct problem and solution choices?
\[25^{z+4}=125\] \[5^{2(z+4)}=5^3\] \[2z+8=3\] solve for \(z\)
yes, i'm sure
so it is not A, you have to solve \[2z+8=3\]\[2z=-5\]\[z=-\frac{5}{2}=-2.5\]
the gimmick is to rewrite so both sides have the same base
Still Need Help?
Join the QuestionCove community and study together with friends!
ohhh.... i see what youre doing...i was way offf!!! ooops
thank you. this helps loads
I see from satelite that z + 4 is an exponent. Now the solution choices make sense.
on the left you have \(25=5^2\) and on the right you have \(125=5^3\)
You meant 25^(z + 4) = 125
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol:
@tinydinoUwU stop trying to find a argument u blad lil boy
TinydinoUwU:
**(Verse 1)** Yo, trapped in a box, Iu2019m feelin' so confined, Lifeu2019s a game of chess, but Iu2019m stuck in rewind, Every dayu2019s a struggle, man, I
Arriyanalol:
hey umm so i need help with my lanauage art ixl anybody wanna help big mama
Nina001:
ho where do i go to buy Subscirption for a moving pfp because on my screen im on
vain:
If the Admins and Mods are ever thinking about a new update for the site; I think what would be cool is that we add a "Profile Music" feature for our profil
Arriyanalol:
so i have a question reading time what is the long hand for then the short hand
14 hours ago
5 Replies
2 Medals
15 hours ago
12 Replies
4 Medals
3 days ago
2 Replies
1 Medal
4 days ago
4 Replies
2 Medals
4 days ago
17 Replies
1 Medal
5 days ago
0 Replies
0 Medals