Question

Choose one of the factors of 5x3 – 135

5

x – 3

x2 + 3x + 9

All of the above

Answer 1

take 5 common from the equation :)

Answer 2

ooops make that \(5(x^3-27)\) as a start, then use
\[a^3-b^2=(a-b)(a^2+ab+b^2)\] with
\[a=x,b=3\]

Answer 3

damn another typo, make that
\[a^3-b^3=(a-b)(a^2+ab+b^2)\] with \(a=x\) and \(b=3\)
just make a direct substitution into the formula for factoring the "difference of two cubes"

Answer 4

@raebaby420 is it clear how to do that?