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OpenStudy (anonymous):
A box contains 5 red balls and 6 black balls. in how many ways can 6 balls be selected so that there are at least two balls of each color?
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OpenStudy (kropot72):
All possible combinations are obtained by selections of 2 red and 4 black, 3 red and 3 black, and 4 red and 2 black. Therefore the required number of ways is (5C2 * 6C4) + (5C3 * 6C3) + (5C4 * 6C2)
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