Question

Factor Completely: 27ab^3 − 36a^2b

Answer 1

\[27ab ^{3}-36a ^{2b}\] Is that what it looks like? But I think you mean
\[27ab ^{3}-36a ^{2}b\]

Answer 2

Anyways, you want to find the factored pairs of both the numbers.

Answer 3

sorry was reading from an older question i had but these are my answer chocies

9a^2b(3b − 4a)
9ab(3b^2 − 4a)
ab(27b^2 − 36a)
9ab(3a − 4b)

Answer 4

Well, 9 is divisible by both 27 and 36
So that gives us:

9(3ab^3−4a^2b)

You can also factor out an a and a b from both sets.

So:
9ab(3b^2−4a)

Answer 5

XD aha, well there you go.

Answer 6

Thank you! xD

Answer 7

Do you kind of understand how to do it? Basically, you just have find the GCF.

Answer 8

yes i get that but i dont understand the variables part

Answer 9

Well, for the variables part.

Answer 10

I'm'actually doing that right now LOL.

Answer 11

give me a second, let me write it out...

Answer 12

ok :) no rush i'm just trying to understand how its done.

Answer 13

XD Let me draw it out.

Answer 14

ok :D

Answer 15

Now you already know GCF is 9. But, since there are variables, you can see what you can take out.