How do you solve:
A statement Sn about the positive integers is given. Write statements S1, S2, and S3, and show that each of these statements is true.

Sn: 12 + 42 + 72 + . . . + (3n - 2)2 = (n(6n^2-3n-1))/2

Question

How do you solve:
A statement Sn about the positive integers is given. Write statements S1, S2, and S3, and show that each of these statements is true. 

Sn:   12 + 42 + 72 + . . . + (3n - 2)2 = (n(6n^2-3n-1))/2

anonymous · Answer

replace $n$ by 1 to get 
$$S_1$$ which will be $$12=\frac{1(6\times 1^2-3\times 1-1)}{2}$$which does not seem to be true does it?

anonymous · Answer

no it does not it equals 0

anonymous · Answer

and sorry it was 1^2+4^2+7^2 then (3n-2)^2