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Mathematics 9 Online
OpenStudy (anonymous):

can someone show me the steps on how to solve to find the zeros of x4-15x2-16, or x3+4x2-3x-12, or x4+2x3+2x2+2x+1

OpenStudy (anonymous):

factor as \[(x^2-16)(x^2+1)=0\]

OpenStudy (anonymous):

Finding zeroes just means finding the roots of this quadratic equation

OpenStudy (anonymous):

or another way of saying the same thing is where the graph touches the x-axis

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