Question

3x^2-4x=-1

Answer 1

If u have a equation
ax^2+bx+c=0
first find d=a*c
Then find two factors e and f of d such that
e*f=d
e+f=b
Then distribute the middle term bx using e and f and then start factorising by grouping two terms.
Does that help?

Answer 2

@Brandon1996

Answer 3

this looks like some of those questions I need help on lol

Answer 4

Kind of, but where are you getting all of the extra variables (d, e, f) ?

Answer 5

ax^2+bx+c=0
the equation given is 3x^2-4x+1=0 (3x^2-4x=-1=>3x^2-4x+1=0)
so a=3, b=-4 and c=1
Nw let us find d.
d=a*c
=3*1
=3
Nw u need to find factors e and f of d. to that let me list out the factors of d.
1,3,-1,-3
e+f=b
e+f=-4
-1-3=-4
so
e=-1 and f=-3
Nw let us distribute the mid term
-4x=-x-3x
3x^2-x-3x+1=0
3x^2-3x-x+1=0
Nw factorise
3x^2-3x and -x+1
and combine the results

Answer 6

Thank you soo much!

Answer 7

Well this method I showed is to find the values of x using facorinsing method.
If u wanna find x u can use quadratic formula too.

a=3, b=-4 and c=1