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Evaluate :- \[\tan[\frac{1}{2}\cos^{-1}\frac{3}{5}].\]
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use half angle formula of tan
tan x=??
\[\tan x= \frac{2 \tan \frac{x}{2}}{1+\tan^2{\frac{x}{4}}}.\]
Why not draw a triangle? :-P
am I ryt?
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no ... that's not correct.
then where is the mistake ?
you can use this : \(\huge \arccos x = 2 \arctan \frac{\sqrt{1-x^2}}{1+x}\)
x/4
is it x/2
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yes
is this correct?
i think it's not Please help :)
only the componendo dividendo part is incorrect
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it'll be -tan^2x/1 =-2/8
ya i also thought about that
thanx everyone fot their help. i gt it:)
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