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OpenStudy (maheshmeghwal9):
Evaluate :- \[\tan[\frac{1}{2}\cos^{-1}\frac{3}{5}].\]
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OpenStudy (experimentx):
use half angle formula of tan
OpenStudy (experimentx):
tan x=??
OpenStudy (maheshmeghwal9):
\[\tan x= \frac{2 \tan \frac{x}{2}}{1+\tan^2{\frac{x}{4}}}.\]
Parth (parthkohli):
Why not draw a triangle? :-P
OpenStudy (maheshmeghwal9):
am I ryt?
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OpenStudy (experimentx):
no ... that's not correct.
OpenStudy (maheshmeghwal9):
then where is the mistake ?
hartnn (hartnn):
you can use this : \(\huge \arccos x = 2 \arctan \frac{\sqrt{1-x^2}}{1+x}\)
OpenStudy (experimentx):
x/4
OpenStudy (maheshmeghwal9):
is it x/2
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OpenStudy (experimentx):
yes
OpenStudy (maheshmeghwal9):
OpenStudy (maheshmeghwal9):
is this correct?
OpenStudy (maheshmeghwal9):
i think it's not Please help :)
hartnn (hartnn):
only the componendo dividendo part is incorrect
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hartnn (hartnn):
it'll be -tan^2x/1 =-2/8
OpenStudy (maheshmeghwal9):
ya i also thought about that
OpenStudy (maheshmeghwal9):
thanx everyone fot their help. i gt it:)
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