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OpenStudy (anonymous):

complete the square: x^2-2x

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Parth (parthkohli):

Add and subtract \(\left(\dfrac{-2}{2}\right)^2\) to start with.

OpenStudy (anonymous):

what?

hartnn (hartnn):

what is the co-efficient of 'x' in your expression ?

OpenStudy (anonymous):

2

hartnn (hartnn):

its -2 now divide it by 2, what u get ?

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OpenStudy (anonymous):

-1

hartnn (hartnn):

square it, what u get ?

OpenStudy (anonymous):

1

hartnn (hartnn):

now add and subtract one , what u get ?

OpenStudy (anonymous):

0 and 2?

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hartnn (hartnn):

those are roots, but you wouldn't have completed the square then... you get x^2-2x +1 -1 right ?

hartnn (hartnn):

notice that x^2-2x+1 is a perfect square

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