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Mathematics 17 Online
OpenStudy (anonymous):

Math help please ?

OpenStudy (anonymous):

OpenStudy (anonymous):

I have 1 and 2 I need help with the rest

OpenStudy (anonymous):

for the third one you have \[\sqrt{128*x^5*y^2} = \sqrt{16*8*x^2*x^2*x*y^2} \] \[= x*x*y\sqrt{4^2*2^2*2*x}= x^2*y*4*2*\sqrt{2x} = 8x^2y\sqrt{2x}\]

OpenStudy (anonymous):

Thats really confusing :/

OpenStudy (anonymous):

@tomo

OpenStudy (anonymous):

sqrt(x^2) = x that is the fundamental realization you must make the square root of something squared is always just that something

OpenStudy (anonymous):

I dont get it

OpenStudy (anonymous):

if you don't understand square roots, then you should really look at these videos https://www.khanacademy.org/math/arithmetic/exponents-radicals/radical-radicals/v/understanding-square-roots

OpenStudy (anonymous):

I do understand them, I just dont understand you.

OpenStudy (anonymous):

@swalehe do you know ?

OpenStudy (anonymous):

you just break up the different expressions until you have something in the form x^2

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