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The hypotenuse if a right triangle is 3cm linger than twice the length of the shorter leg. The longer leg measures 12cm . Find the lengths of the shorter leg and the hypotenuse
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|dw:1363194740714:dw|
I can't see the while pic
Whole
what part can't you see?
Half, i only see 12 abd letter s
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and*
oh okay. the hypotenuse has 3+2s on it. S is your base, and 12 is the height/larger leg
What will be the equation? 3+2s+s=12?
Not exactly. You would have to be using the Pythagorean theorem I think. so A^2 + B^2 = C^2. A^2 is 144, B^2 is the same as saying S^2, and C^2 = 4s^2 + 12s + 9
So entire equation put together: 144 + S^2 = 4s^2 + 12s + 9
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Oh wait i'll try to solve
I got x=9?
That is what I got
So the hypotenuse is 21 and shorter leg is 9?
yes
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