Question

What is the 9th term of the geometric sequence where a1 = -6 and a6 = -6,144? (1 points)
Answer

-327,680

-393,216

-458,752

-524,288

Answer 1

a_n*r^n = nth term

Answer 2

ok please teach me how i set it up?

Answer 3

what do i put in for "n"?

Answer 4

hold on i am on it.

Answer 5

formula is off a bit

formula is this

a*r^(n-1) = nth term

so first term is
-6
cuzz if we plug it in
a * r^( 1-1) = -6
^ that is 0
a * r^0 =-6
^ that is 1 cuzz anynumber to the 0th is 1 just a rule
a=-6
so now we know a and plug it into the a6 6th term
a *r^(n-1) = nth term
-6 *r^(6-1) = -6144
-6 * r^5 = 6144 sfr r = -4

so now we have all variables a = - 6 and r is 4

so plug it into formula
a*r^(n-1) = nth term
-6*4^(9-1)= -393216

Answer 6

the problem was that you solved it entirely by yourself @timo86m instead of making her solve...

Answer 7

no offense @timo86m but he's right... I don't learn that way

Answer 8

The problem is that someone might not always be here for you so you need the answer for confirmation.