Question

Find the domain of the function g(x)= x+9/x^2-1

Answer 1

All real numbers not equal to 1, -1.

Since N/0 = infinity or indeterminant, we find the zeroes of the bottom. Which are 1 and -1.

Answer 2

Unclear:

\(g(x) = x + \dfrac{9}{x^{2}} - 1\)

\(x\ne 0\)

\(g(x) = \dfrac{x+9}{x^{2}-1}\)

\(x\ne 1\;and\;x\ne -1\)

Answer 3

Thank you for your help!

Answer 4

I guess we'll never know he correct answer.