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Mathematics 9 Online
OpenStudy (ksaimouli):

limit

OpenStudy (ksaimouli):

\[\lim_{x \rightarrow 0^+}(3x^{2x})\]

OpenStudy (ksaimouli):

@ghazi

OpenStudy (ksaimouli):

i got 1

OpenStudy (ghazi):

i am getting something weird lol

OpenStudy (ghazi):

i got 3

OpenStudy (ghazi):

let me solve it

OpenStudy (ksaimouli):

ya how did u get that

OpenStudy (ghazi):

\[3( \lim_{x \rightarrow 0} x^{2x})\] now

OpenStudy (ghazi):

use this :D \[x^{2x}=e^{\lim_{x \rightarrow 0}2xlogx}\] i think now you can do it ;)

OpenStudy (ksaimouli):

i did similarly correct me if i am wrong

OpenStudy (ghazi):

\[3e^{2(\lim_{x \rightarrow 0}xlogx)}\]

OpenStudy (ksaimouli):

\[lnf(x)=\ln 3x^{2x}\] \[lnf(x)=2xln(3x)\]

OpenStudy (ghazi):

\[put, t=\frac{ 1 }{ x }\]

OpenStudy (ksaimouli):

so to use l' hopitals rule

OpenStudy (ghazi):

\[3e^{2 \lim \lim_{t \rightarrow \infty} \log \frac{ 1 }{ t }/t}\]

OpenStudy (ksaimouli):

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