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\[\lim_{x \rightarrow 0^+}(3x^{2x})\]
@ghazi
i got 1
i am getting something weird lol
i got 3
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let me solve it
ya how did u get that
\[3( \lim_{x \rightarrow 0} x^{2x})\] now
use this :D \[x^{2x}=e^{\lim_{x \rightarrow 0}2xlogx}\] i think now you can do it ;)
i did similarly correct me if i am wrong
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\[3e^{2(\lim_{x \rightarrow 0}xlogx)}\]
\[lnf(x)=\ln 3x^{2x}\] \[lnf(x)=2xln(3x)\]
\[put, t=\frac{ 1 }{ x }\]
so to use l' hopitals rule
\[3e^{2 \lim \lim_{t \rightarrow \infty} \log \frac{ 1 }{ t }/t}\]
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