How do you solve 5(k-2)= 0
you would go thought the order of operations to get k isolated.
By multiplying 5 by k then 5 by 2?
so dividing by 5 on each side will get k-2=0 than just add two to each side and get k=2 :)
Would this be quadratic equations?
Well, its on my quadratics homework, so I would think so, yes
haha, yes, since there is the 5(x-2) its considered a factored equation
Keep in mind if there isn't a variable on the first constant it wouldn't be considered to be equal to 0.
so what would the answer be?
Then as nicole said, replace the positive 2 with the variable. 5(2-2)=0 the above would be correct. And your answer would be k = 2 <-- the 2 would be the answer in this case
Not sure if I explained so you could understand tho.. im horrible at explaining
Great. Thanks a bunch to both of you
need anymore help? :)
No, I understand how to do it now. Thanks again
No problem. =)
-7(2y-1)y=0
would the answer be for that question y = 1/2, 0
Yep, plug them in to check if they end up to = to 0 and you'd be correct.
Lol, both are good.
Haha thanks :)
No prob. :)
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