Is 2m^2 + 13m + 15 prime?
Because i cant find a way to sove this problem Help please?
use the quadratic formula, but keep in mind that you need an equation for this and what you have posted is simply what is called an "expression", it may "evaluate" to a prime number for a given value of m but as an expression this dosent mean much, there's probably an equal sign in the problem somewhere that you left out when you posted the expression
no it is not prime
How? and im talking about factoring it...
You can find factors for this trinomial by multiplying the coefficient of your squared term times the constant. You must then find factors of this result which add to the coefficient of your middle term.
In other words, what are the factors of 2x15=30 which give you a sum of 13. axb=30 and a+b=13
\[(m+5)(m+\frac{ 3 }{ 2 })\]
wait so is it 2(m+10)(m+3)
You cannot factor out a 2 because not all the terms are divisible by two.
just a not on terminology, if by "prime" you mean it cant be factored then we say "unfactorable"
so (2m+10) (m+3) (im just taken shots in the dark here)
u can write \[2m^2+13m+15=>2m^2+10m+3m+5\]
\[now , 2m(m+5)+3(m+5)\]
\[(2m+3)(m+5)\]
oohhhh i see ok
Thank You! :)
my pleasure :)
@twisted,do you see how she split up the middle term? That is because the factors of 30 which add to 13 are 10 and 3.
oops @Twisted_Ouroborous
lol XD and yes i do
Great!
Join our real-time social learning platform and learn together with your friends!