Question

the chalkboard in the algebra classroom covers 88 square feet of area. If the length is 5.5 times the height, what are the dimensions of the board?

Answer 1

Draw a diagram of a basic rectangle. One side has a length of x, which you don't know, and the other side has a length of 5.5*x, as stated in the problem. You also know that the area of a standard rectangle is length*width... So how would you set this one up?

Answer 2

What are you trying to do?

Answer 3

solve the problem

Answer 4

You know the area is A = length*width. You know the area is 88, and the side lengths are x, and 5.5x. Use these facts

Answer 5

x=16

Answer 6

Not quite.\[5.5x^2=88\] Hence, \[x^2 = 16\]
So what can you say about x?

Answer 7

x=4

Answer 8

the dims are 4 and 22

Answer 9

Yep, sounds good to me.

Answer 10

ty!!