Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

the chalkboard in the algebra classroom covers 88 square feet of area. If the length is 5.5 times the height, what are the dimensions of the board?

OpenStudy (anonymous):

Draw a diagram of a basic rectangle. One side has a length of x, which you don't know, and the other side has a length of 5.5*x, as stated in the problem. You also know that the area of a standard rectangle is length*width... So how would you set this one up?

OpenStudy (anonymous):

What are you trying to do?

OpenStudy (anonymous):

solve the problem

OpenStudy (anonymous):

You know the area is A = length*width. You know the area is 88, and the side lengths are x, and 5.5x. Use these facts

OpenStudy (anonymous):

x=16

OpenStudy (anonymous):

Not quite.\[5.5x^2=88\] Hence, \[x^2 = 16\] So what can you say about x?

OpenStudy (anonymous):

x=4

OpenStudy (anonymous):

the dims are 4 and 22

OpenStudy (anonymous):

Yep, sounds good to me.

OpenStudy (anonymous):

ty!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!