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Am I setting this problem up correctly? Solve 3^x-4 = 7^ x+9 (x - 4) log 3 = (x + 9) = log 7
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huh :(
i got 12...
x = 4 In (3) + 9 In (7)/In (3) - In (7)
THANK YOU FOR THE STEPS!!!!!!!!!!!!!!!!!!
but i still got 12
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i used the calc magic and let me just tell you this....there was no magic!!!!!!!
@Luis_Rivera
(x - 4) log 3 = (x + 9) log 7 xL3 - 4L3 = xL7 + 9L7 xL3 - xL7 = 4L3 + 9L7 x(L3 - L7) = 4L3 + 9L7 4L3 + 9L7 x = ---------- L3 - L7
where did L come from???????????????????
oh Log:)
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im sure it can be cleaned up a little more, but thats the gist of it .... and yes, L for log
2.38061585769
... mine says -25.86 or so
3^x-4 = 7^ x+9 those are exponents right?
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