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Mathematics 22 Online
OpenStudy (anonymous):

Solve the system by using elimination.

OpenStudy (anonymous):

OpenStudy (mertsj):

1. Add equations 1 and 3 2. Add equations 2 and 3 3. You will now have two equations with only y and z 4. Solve that system

OpenStudy (anonymous):

okay one sec

OpenStudy (anonymous):

okay so far i have 7y+10z=7 @Mertsj

OpenStudy (mertsj):

So now add 2 and 3

OpenStudy (anonymous):

i did i got 5y+6z+5 and 2y+4z=2 i added them together to get that answer

jimthompson5910 (jim_thompson5910):

Add equations 1 and 3 to get 5y+6z = 5 Add equations 2 and 3 to get 2y+4z = 2

jimthompson5910 (jim_thompson5910):

so it looks like you got it

jimthompson5910 (jim_thompson5910):

you now have this smaller system 5y+6z = 5 2y+4z = 2

jimthompson5910 (jim_thompson5910):

let's say we want to eliminate z, we would multiply the top equation by 2 and the bottom equation by -3 to get 2(5y+6z) = 2*5 -3(2y+4z) = -3*2 10y+12z = 10 -6y-12z = -6

jimthompson5910 (jim_thompson5910):

notice how there's a +12z and a -12z, they would add to 0z or just 0 (and it would cancel and go away)

OpenStudy (anonymous):

so then would we do the same for y

jimthompson5910 (jim_thompson5910):

from here, just add the equations

jimthompson5910 (jim_thompson5910):

10y+12z = 10 -6y-12z = -6 ------------- 4y +0z = 4 4y = 4 y = ??

OpenStudy (anonymous):

oh okay so 1

jimthompson5910 (jim_thompson5910):

so each step of elimination eliminates one variable (first you eliminated x, then you eliminated z)

jimthompson5910 (jim_thompson5910):

yes y = 1

jimthompson5910 (jim_thompson5910):

so 10y + 12z = 10 10(1) + 12z = 10 10 + 12z = 10 ... z = ??

jimthompson5910 (jim_thompson5910):

and you probably see from here how to find x (given y and z)

OpenStudy (anonymous):

yes thank you!!! could you pretty please help with one more??

jimthompson5910 (jim_thompson5910):

ok just one more

OpenStudy (anonymous):

k, we have to solve with substiution give me a sec and i'll have the pic

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

solve for either x or z in the last equation

OpenStudy (anonymous):

so we add -x nd 2x to get rid of x ?

jimthompson5910 (jim_thompson5910):

idk what you mean

jimthompson5910 (jim_thompson5910):

in the third equation, do you want to solve for x or z?

OpenStudy (anonymous):

z?

jimthompson5910 (jim_thompson5910):

ok so what do you get when you isolate z in the third equation

OpenStudy (anonymous):

2x+2=4?

jimthompson5910 (jim_thompson5910):

2x + 2z = 4 2z = -2x + 4 z = -2x/2 + 4/2 z = -x + 2

jimthompson5910 (jim_thompson5910):

that's what you should get when you solve for z

jimthompson5910 (jim_thompson5910):

then you replace each 'z' you see in equations 1 and 2 with -x+2

jimthompson5910 (jim_thompson5910):

that will give you two equations in terms of x and y

OpenStudy (anonymous):

do we do this for all the variables?

jimthompson5910 (jim_thompson5910):

yes you solve for one variable and plug it into the other equation

jimthompson5910 (jim_thompson5910):

that effectively eliminates variables until you're left with one to solve for

OpenStudy (anonymous):

so how would i do the next line

jimthompson5910 (jim_thompson5910):

what do you get when you plug in z = -x + 2

OpenStudy (anonymous):

sorry i messed that up

OpenStudy (anonymous):

-x-y(-x+2)=-8 -4x+4y+5(-x+2)=7 2x+2(-x+2)=4?

jimthompson5910 (jim_thompson5910):

ignore the last equation

jimthompson5910 (jim_thompson5910):

-x - y - z = -8 would turn into -x - y - (-x + 2) = -8

jimthompson5910 (jim_thompson5910):

-4x + 4y + 5z = 7 turns into -4x + 4y + 5(-x+2) = 7

OpenStudy (anonymous):

what next?

jimthompson5910 (jim_thompson5910):

solve -x - y - (-x + 2) = -8 for y

OpenStudy (anonymous):

Can I have a hint?

jimthompson5910 (jim_thompson5910):

-x - y - (-x + 2) = -8 -x - y + x - 2 = -8 -y - 2 = -8 ... y = ??

jimthompson5910 (jim_thompson5910):

close

jimthompson5910 (jim_thompson5910):

very close

OpenStudy (anonymous):

6

jimthompson5910 (jim_thompson5910):

yes y = 6

OpenStudy (anonymous):

so now we have to do x?

jimthompson5910 (jim_thompson5910):

plug in y = 6 into -4x+4y+5(-x+2)=7 to find x

OpenStudy (anonymous):

so -4x+4(6)+5(-x+2)=7 and then solve for x?

jimthompson5910 (jim_thompson5910):

yes exactly

OpenStudy (anonymous):

okay so -4x+24+5(-x+2)=7 -4x+29(-x+2)=7 how do i work the -x+2

jimthompson5910 (jim_thompson5910):

-4x+24+5(-x+2)=7 -4x+24-5x+10=7 -9x+34=7 ... x = ??

OpenStudy (anonymous):

3?

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

then use this value of x to find z

OpenStudy (anonymous):

so z = -1?

jimthompson5910 (jim_thompson5910):

yep

jimthompson5910 (jim_thompson5910):

summary: x = 3, y = 6, z = -1

OpenStudy (anonymous):

Wow alot of work! Thank you soo much I really appreciate it!!

jimthompson5910 (jim_thompson5910):

yw

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