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whats the integral of ln(x^(2) + 1)??
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so far I have:\[\ln(x ^{2}+1)x-\int\limits_{}^{}x*\frac{ 2x }{ x ^{2}+1 } dx\]
Long division for the int. by parts?
uhmm could that work?
my guess is parts
oh nvm you have that already
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\[\ln(x ^{2}+1)x-\int\limits\limits_{}^{}2-\frac{2}{x^2+1} dx \]
\[\frac{x^2}{x^2+1}=\frac{x^2+1}{x^2+1}-\frac{1}{x^2+1}=1-\frac{1}{x^2+1}\]
first integral is obvious, second part is the derivative of arctangent
i ignored the 2, @.Sam. has it
you could divide too, but i find that gimmick easier than long division
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thank you! I'll try and post it when im done :P
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