Question

where is everyone?!? help please! =(
find the extrema: 4x^3-13x^2+4x+1
max and min:
[1,4]
[0,2]

Answer 1

so i found the derivative: 12x^2 -26x +4

Answer 2

correct?

Answer 3

I could maybe figure it out for myself on my calculator but I don't know how that would help, are you in webworks?

Answer 4

yup.

Answer 5

do you know hot to factor: 12x^2 -26x +4

Answer 6

I'll try and see if I can help but can't promise
so yeah you have the derivative right

Answer 7

not on calculator though... i just need to know just in case.

Answer 8

i must factor first in order to = to 0

Answer 9

so to find max and min you find the derivative set it = to 0 and solve?

Answer 10

yes i have to find the critical points.. then evaluate the point to original function

Answer 11

then evaluate with the endpoints. then i'll find max and min

Answer 12

so you have 1/6 and 2 for the critical points right?

Answer 13

@campbell_st @precal @heradog the more help the better! :( i really need to figure this problem out.

Answer 14

well.... i don't know how to factor this exactly: 12x^2 -26x +4

Answer 15

since derivative is right... then how do i factor it out?

Answer 16

@dan815