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Physics 8 Online
OpenStudy (anonymous):

A thin uniform rod of length L and mass m is swinging freely about a horizontal axis passing through its end. Its maximum angular speed is w. Calculate to what maximum height the centre of mass rises

OpenStudy (anonymous):

@shubhamsrg @Mashy

OpenStudy (shubhamsrg):

cons. of energy should help

OpenStudy (anonymous):

hmmph.. max velocity is at the mean position!.. so you probably use energy conservation!

OpenStudy (shubhamsrg):

^_^

OpenStudy (anonymous):

K.E = P.E

OpenStudy (anonymous):

1/2 I w^2 = I g h

OpenStudy (shubhamsrg):

mgh*

OpenStudy (shubhamsrg):

got the ans right ?

OpenStudy (anonymous):

i dont have answer key with me

OpenStudy (shubhamsrg):

I am getting l^2 w^2 /6g

OpenStudy (shubhamsrg):

thats " L" and not " i"

OpenStudy (anonymous):

I = ml^2/3

OpenStudy (anonymous):

use linear quantities.. cause Centre of mass is asked..

OpenStudy (anonymous):

ok..thxx Guys for ur help....

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