A body of mass m, moving at velocity v, collides with a stationary body of the same mass and sticks to it. Which expression describes the kinetic energy of the two bodies after collision?

Question

anonymous · Answer

a) 1/4mv^2
b) 1/8mv^2
c) 1/2 mv^2
d) mv^2

anonymous · Answer

The best suggestion that I can offer is to find the momentum. Sorry I forgot the formula and this is the mathematics section not the physics. Sorry that I couldn't help enough.

anonymous · Answer

maybe it should be C...

anonymous · Answer

maybe it should be in physics section

anonymous · Answer

I study this in Mechanics section of Maths! :O

anonymous · Answer

m*v = p (momentum), in an isolated system, ignoring all effects of friction, the P(before) = P(after) therefore,   | before -(mass of obj 1 * vel of obj1) +  (mass of obj 2 * vel of obj2) |  =  | after -(mass of obj 1 * vel of obj1) +  (mass of obj 2 * vel of obj2) |, u can addapt formula aswel, mv1 + mv2 = (when obj combine) m(v1+v2) hope it makes sense

anonymous · Answer

mechanics comes in physics x/
i meant you will get better answers if u try physics section

anonymous · Answer

@aajugdar : I know that but people don't answer there much. :P
@cybergurken : Thank you.